expansion plugs in oil galleys

[olman]

I have a C6ME-A  390 block with a 7C29 casting date from DIF . Removed all the expansion plugs from the block to clean the oil passages.  Is it common to find a block that that is not tapped for  1/4 inch pipe plugs on the rear of the block around the cam plug. All 10 galley holes had expansion plugs. Just curious.

[440sixpack]

I'm sure someone knows more about it than me, but I know they don't all come tapped because my machine shop just did it on my 428.

[Barry_R]

Very common.

[olman]

Barry, I ordered a brass core plug kit from Elgin for the FE blocks and brass plugs are marked 1 3/4" on plugs. In your book you recommend to use 1 49/64. Which manufacturers kit comes with the correct size. I see in your book you have a Pioneer PB-110-B kit but I don't know if it's 1 49/64 or
1 3/4" Did an internet search for them but none show the size of the core plug.

[Barry_R]

I like the larger plug.  Those holes do not get smaller in diameter after a few plugs get pounded in and out over the past fifty years....

[cjshaker]

Those holes do not get smaller in diameter after a few plugs get pounded in and out over the past fifty years....

So many comments to make, so little time

[GJCAT427]

Ah Doug did we skip the meds again!?

[Barry_R]

I thin k Doug has taken the opportunity to go off topic....

[My427stang]

Those holes do not get smaller in diameter after a few plugs get pounded in and out over the past fifty years....

So many comments to make, so little time

ROFL

[C6AE]

Some math can be reassuring here.
A 1/4" dia. press fit plug at 100 psi will have only 5 lbs of pressure pushing against it.

[Heo]

 

Those holes do not get smaller in diameter after a few plugs get pounded in and out over the past fifty years....

So many comments to make, so little time

 

[Barry_R]

Some math can be reassuring here.
A 1/4" dia. press fit plug at 100 psi will have only 5 lbs of pressure pushing against it.

Can one of you engineering types verify this?  For some reason I think its off a bit ... F=P/A?

[blykins]

Pressure equals force over area.   P=F/A

So F = PA

Force (lbs) = 100 lbs/in^2 * .049 in^2 = 4.9 lbs.

Seems counterintuitive, doesn't it? 

[My427stang]

P=F/A

If you solve for F, then F=PA

The area of a .250 circle is only 0.049087385212341 square inches.

If the pressure is 100 psi, then actual force against the surface of the cup should be just under 5 lbs.

F = 100*0.049087385212341

F = 4.9 and change

What I don't know is what the pressure is to push the cup back out, likely not much, but in terms of hydraulic pressure, that does work in the thousands of PSI, the oil galleys aren't pushing that hard and have plenty of leaks enroute as pressure backs up

[My427stang]

Great minds think alike...scary one of them has a business degree